(2/3)^x+8=(3/2)^2x-5

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Solution for (2/3)^x+8=(3/2)^2x-5 equation: 



(2/3)^x+8=(3/2)^2x-5

We move all terms to the left:

(2/3)^x+8-((3/2)^2x-5)=0



Domain of the equation: 3)^x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 2)^2x-5)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)^x-((+3/2)^2x-5)+8=0

We calculate fractions


4^2x/3^x*2)^2x-5))+(-9^x/3^x*2)^2x-5))+8=0

We can not solve this equation

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